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400x^2-9.8x-17.64=0
a = 400; b = -9.8; c = -17.64;
Δ = b2-4ac
Δ = -9.82-4·400·(-17.64)
Δ = 28320.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.8)-\sqrt{28320.04}}{2*400}=\frac{9.8-\sqrt{28320.04}}{800} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.8)+\sqrt{28320.04}}{2*400}=\frac{9.8+\sqrt{28320.04}}{800} $
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