402-8(6x+41)-5(16-3x)-41=604-(13x+51)

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Solution for 402-8(6x+41)-5(16-3x)-41=604-(13x+51) equation:



402-8(6x+41)-5(16-3x)-41=604-(13x+51)
We move all terms to the left:
402-8(6x+41)-5(16-3x)-41-(604-(13x+51))=0
We add all the numbers together, and all the variables
-8(6x+41)-5(-3x+16)-(604-(13x+51))+402-41=0
We add all the numbers together, and all the variables
-8(6x+41)-5(-3x+16)-(604-(13x+51))+361=0
We multiply parentheses
-48x+15x-(604-(13x+51))-328-80+361=0
We calculate terms in parentheses: -(604-(13x+51)), so:
604-(13x+51)
determiningTheFunctionDomain -(13x+51)+604
We get rid of parentheses
-13x-51+604
We add all the numbers together, and all the variables
-13x+553
Back to the equation:
-(-13x+553)
We add all the numbers together, and all the variables
-33x-(-13x+553)-47=0
We get rid of parentheses
-33x+13x-553-47=0
We add all the numbers together, and all the variables
-20x-600=0
We move all terms containing x to the left, all other terms to the right
-20x=600
x=600/-20
x=-30

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