404=2+6(3+8x)

Solution for 404=2+6(3+8x) equation:

404=2+6(3+8x)

We move all terms to the left:

404-(2+6(3+8x))=0

We add all the numbers together, and all the variables

-(2+6(8x+3))+404=0


We calculate terms in parentheses: -(2+6(8x+3)), so:

2+6(8x+3)

determiningTheFunctionDomain
6(8x+3)+2

We multiply parentheses

48x+18+2

We add all the numbers together, and all the variables

48x+20

Back to the equation:

-(48x+20)


We get rid of parentheses

-48x-20+404=0

We add all the numbers together, and all the variables

-48x+384=0

We move all terms containing x to the left, all other terms to the right

-48x=-384

x=-384/-48

x=+8