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ln(1-cos(x^2))
(1/(2*3.14*x))*(a^2-b^2)^(1/2)
3.14*(1/2)*x*(a^2-b^2)^(1/2)
(1/x)*(a^2-b^2)^(1/2)
1*x^3+12*x^2+39*x+28 = 0;x
x
| 9(n-1)+h=11 | | 4x+3y=219 | | 20x+5=9x-2+20x+5 | | X=-4y-3y | | 9.28+2x=28.14 | | x^2-6x-56= | | 225-16t(t)=0 | | 28r=1764 | | 9.1m+12.6=4.9m | | y=in(2x^3-3x^2+4) | | 15x+10=20x-150 | | (x-10)2+(x-6)2=32 | | 5n-2n+4n= | | 50=0.18*x | | -9b^2=-8a+8 | | 32/w=8 | | c(21-c)=110 | | 18x-15=-69 | | y=in(ax^2+b) | | -9b^2=-8a-4 | | 4-4x-x^2=0 | | 50=0.34*x | | t^2+4n-45= | | 8x-3x+2y=-21 | | 3x+4y+4=26 | | 60-6x=x | | G+7=19 | | 50x+520=40x | | 6t-6=14 | | 3(8.3)-4.1+4(x)= | | 50x+520=40 | | (28b-3)-9(3b+2)=-3 |