40=(2/5)x+2

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Solution for 40=(2/5)x+2 equation: 



40=(2/5)x+2

We move all terms to the left:

40-((2/5)x+2)=0



Domain of the equation: 5)x+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+2/5)x+2)+40=0

We multiply all the terms by the denominator


-((+2+40*5)x+2)=0



We calculate terms in parentheses: -((+2+40*5)x+2), so:

(+2+40*5)x+2

We add all the numbers together, and all the variables

202x+2

Back to the equation:

-(202x+2)



We get rid of parentheses

-202x-2=0

We move all terms containing x to the left, all other terms to the right

-202x=2

x=2/-202

x=-1/101

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