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40=(2/5)y
We move all terms to the left:
40-((2/5)y)=0
Domain of the equation: 5)y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-((+2/5)y)+40=0
We multiply all the terms by the denominator
-((+2+40*5)y)=0
We calculate terms in parentheses: -((+2+40*5)y), so:y=0/-202
(+2+40*5)y
We add all the numbers together, and all the variables
202y
Back to the equation:
-(202y)
y=0
Równanie nie ma rozwiązania
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