40=(2w+2)w

Solution for 40=(2w+2)w equation:

40=(2w+2)w

We move all terms to the left:

40-((2w+2)w)=0


We calculate terms in parentheses: -((2w+2)w), so:

(2w+2)w

We multiply parentheses

2w^2+2w

Back to the equation:

-(2w^2+2w)


We get rid of parentheses

-2w^2-2w+40=0

a = -2; b = -2; c = +40;
Δ = b2-4ac
Δ = -22-4·(-2)·40
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*-2}=\frac{-16}{-4}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*-2}=\frac{20}{-4}
=-5
$