40=(3x-53)/10

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Solution for 40=(3x-53)/10 equation: 



40=(3x-53)/10

We move all terms to the left:

40-((3x-53)/10)=0

We multiply all the terms by the denominator


-((3x-53)+40*10)=0



We calculate terms in parentheses: -((3x-53)+40*10), so:

(3x-53)+40*10

We add all the numbers together, and all the variables

(3x-53)+400

We get rid of parentheses

3x-53+400

We add all the numbers together, and all the variables

3x+347

Back to the equation:

-(3x+347)



We get rid of parentheses

-3x-347=0

We move all terms containing x to the left, all other terms to the right

-3x=347

x=347/-3

x=-115+2/3

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