40=(4(-x-6))/3

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Solution for 40=(4(-x-6))/3 equation: 



40=(4(-x-6))/3

We move all terms to the left:

40-((4(-x-6))/3)=0

We add all the numbers together, and all the variables

-((4(-1x-6))/3)+40=0

We multiply all the terms by the denominator


-((4(-1x-6))+40*3)=0



We calculate terms in parentheses: -((4(-1x-6))+40*3), so:

(4(-1x-6))+40*3

We add all the numbers together, and all the variables

(4(-1x-6))+120



We calculate terms in parentheses: +(4(-1x-6)), so:

4(-1x-6)

We multiply parentheses

-4x-24

Back to the equation:

+(-4x-24)



We get rid of parentheses

-4x-24+120

We add all the numbers together, and all the variables

-4x+96

Back to the equation:

-(-4x+96)



We get rid of parentheses

4x-96=0

We move all terms containing x to the left, all other terms to the right

4x=96

x=96/4

x=24

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