40=(8-2x)(12-2x)x

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Solution for 40=(8-2x)(12-2x)x equation: 



40=(8-2x)(12-2x)x

We move all terms to the left:

40-((8-2x)(12-2x)x)=0

We add all the numbers together, and all the variables

-((-2x+8)(-2x+12)x)+40=0

We multiply parentheses ..

-((+4x^2-24x-16x+96)x)+40=0



We calculate terms in parentheses: -((+4x^2-24x-16x+96)x), so:

(+4x^2-24x-16x+96)x

We multiply parentheses

4x^3-24x^2-16x^2+96x

We do not support expression: x^3

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