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40=-1/3(9x+30)+3
We move all terms to the left:
40-(-1/3(9x+30)+3)=0
Domain of the equation: 3(9x+30)+3)!=0We multiply all the terms by the denominator
x∈R
-(-1+40*3(9x+30)+3)=0
We calculate terms in parentheses: -(-1+40*3(9x+30)+3), so:We add all the numbers together, and all the variables
-1+40*3(9x+30)+3
determiningTheFunctionDomain 40*3(9x+30)-1+3
We add all the numbers together, and all the variables
40*3(9x+30)+2
Wy multiply elements
120x(9+2
Back to the equation:
-(120x(9+2)
-(120x11=0
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