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40=-1/3(9x+30+2
We move all terms to the left:
40-(-1/3(9x+30+2)=0
Domain of the equation: 3(9x+30+2)+40!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3(9x+30+2)!=-40
x∈R
-(-1/3(9x+32)+40=0
We multiply all the terms by the denominator
-(-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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