40=-10(t-12)

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Solution for 40=-10(t-12) equation: 



40=-10(t-12)

We move all terms to the left:

40-(-10(t-12))=0



We calculate terms in parentheses: -(-10(t-12)), so:

-10(t-12)

We multiply parentheses

-10t+120

Back to the equation:

-(-10t+120)



We get rid of parentheses

10t-120+40=0

We add all the numbers together, and all the variables

10t-80=0

We move all terms containing t to the left, all other terms to the right

10t=80

t=80/10

t=8

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