40=-4(3b-10)+12b

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Solution for 40=-4(3b-10)+12b equation: 



40=-4(3b-10)+12b

We move all terms to the left:

40-(-4(3b-10)+12b)=0



We calculate terms in parentheses: -(-4(3b-10)+12b), so:

-4(3b-10)+12b

We add all the numbers together, and all the variables

12b-4(3b-10)

We multiply parentheses

12b-12b+40

We add all the numbers together, and all the variables

40

Back to the equation:

-(40)



We add all the numbers together, and all the variables

=0

b=0/1

b=0

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