40=-5(-2-2z)

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Solution for 40=-5(-2-2z) equation: 



40=-5(-2-2z)

We move all terms to the left:

40-(-5(-2-2z))=0

We add all the numbers together, and all the variables

-(-5(-2z-2))+40=0



We calculate terms in parentheses: -(-5(-2z-2)), so:

-5(-2z-2)

We multiply parentheses

10z+10

Back to the equation:

-(10z+10)



We get rid of parentheses

-10z-10+40=0

We add all the numbers together, and all the variables

-10z+30=0

We move all terms containing z to the left, all other terms to the right

-10z=-30

z=-30/-10

z=+3

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