40=-5(3x-6)+1-(-12-5x)

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Solution for 40=-5(3x-6)+1-(-12-5x) equation: 



40=-5(3x-6)+1-(-12-5x)

We move all terms to the left:

40-(-5(3x-6)+1-(-12-5x))=0

We add all the numbers together, and all the variables

-(-5(3x-6)+1-(-5x-12))+40=0



We calculate terms in parentheses: -(-5(3x-6)+1-(-5x-12)), so:

-5(3x-6)+1-(-5x-12)

determiningTheFunctionDomain
-5(3x-6)-(-5x-12)+1

We multiply parentheses

-15x-(-5x-12)+30+1

We get rid of parentheses

-15x+5x+12+30+1

We add all the numbers together, and all the variables

-10x+43

Back to the equation:

-(-10x+43)



We get rid of parentheses

10x-43+40=0

We add all the numbers together, and all the variables

10x-3=0

We move all terms containing x to the left, all other terms to the right

10x=3

x=3/10

x=3/10

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