40=-5(x-1)(x-5)

Solution for 40=-5(x-1)(x-5) equation:

40=-5(x-1)(x-5)

We move all terms to the left:

40-(-5(x-1)(x-5))=0

We multiply parentheses ..

-(-5(+x^2-5x-1x+5))+40=0


We calculate terms in parentheses: -(-5(+x^2-5x-1x+5)), so:

-5(+x^2-5x-1x+5)

We multiply parentheses

-5x^2+25x+5x-25

We add all the numbers together, and all the variables

-5x^2+30x-25

Back to the equation:

-(-5x^2+30x-25)


We get rid of parentheses

5x^2-30x+25+40=0

We add all the numbers together, and all the variables

5x^2-30x+65=0

a = 5; b = -30; c = +65;
Δ = b2-4ac
Δ = -302-4·5·65
Δ = -400
Delta is less than zero, so there is no solution for the equation