40=-6(-8-3x)-8(1-7x)

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Solution for 40=-6(-8-3x)-8(1-7x) equation: 



40=-6(-8-3x)-8(1-7x)

We move all terms to the left:

40-(-6(-8-3x)-8(1-7x))=0

We add all the numbers together, and all the variables

-(-6(-3x-8)-8(-7x+1))+40=0



We calculate terms in parentheses: -(-6(-3x-8)-8(-7x+1)), so:

-6(-3x-8)-8(-7x+1)

We multiply parentheses

18x+56x+48-8

We add all the numbers together, and all the variables

74x+40

Back to the equation:

-(74x+40)



We get rid of parentheses

-74x-40+40=0

We add all the numbers together, and all the variables

-74x=0

x=0/-74

x=0

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