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40=1/2(115-x)
We move all terms to the left:
40-(1/2(115-x))=0
Domain of the equation: 2(115-x))!=0We add all the numbers together, and all the variables
x∈R
-(1/2(-1x+115))+40=0
We multiply all the terms by the denominator
-(1+40*2(-1x+115))=0
We calculate terms in parentheses: -(1+40*2(-1x+115)), so:
1+40*2(-1x+115)
determiningTheFunctionDomain 40*2(-1x+115)+1
Wy multiply elements
80x(-+1
We use the square of the difference formula
80x(-1
Back to the equation:
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