40=1/2(3x+1)(x+1)

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Solution for 40=1/2(3x+1)(x+1) equation: 



40=1/2(3x+1)(x+1)

We move all terms to the left:

40-(1/2(3x+1)(x+1))=0



Domain of the equation: 2(3x+1)(x+1))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+3x+x+1))+40=0

We multiply all the terms by the denominator


-(1+40*2(+3x^2+3x+x+1))=0



We calculate terms in parentheses: -(1+40*2(+3x^2+3x+x+1)), so:

1+40*2(+3x^2+3x+x+1)

determiningTheFunctionDomain
40*2(+3x^2+3x+x+1)+1

Wy multiply elements

80x(++1

We use the square of the difference formula

80x(+1

Back to the equation:

-(80x(+1)



We add all the numbers together, and all the variables

-(80x1=0

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