40=1/3(3x+30)+2

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Solution for 40=1/3(3x+30)+2 equation: 



40=1/3(3x+30)+2

We move all terms to the left:

40-(1/3(3x+30)+2)=0



Domain of the equation: 3(3x+30)+2)!=0

x∈R



We multiply all the terms by the denominator


-(1+40*3(3x+30)+2)=0



We calculate terms in parentheses: -(1+40*3(3x+30)+2), so:

1+40*3(3x+30)+2

determiningTheFunctionDomain
40*3(3x+30)+1+2

We add all the numbers together, and all the variables

40*3(3x+30)+3

Wy multiply elements

120x(3+3

Back to the equation:

-(120x(3+3)



We add all the numbers together, and all the variables

-(120x6=0

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