40=19+1/4z

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Solution for 40=19+1/4z equation: 



40=19+1/4z

We move all terms to the left:

40-(19+1/4z)=0



Domain of the equation: 4z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-(1/4z+19)+40=0

We get rid of parentheses

-1/4z-19+40=0

We multiply all the terms by the denominator


-19*4z+40*4z-1=0

Wy multiply elements

-76z+160z-1=0

We add all the numbers together, and all the variables

84z-1=0

We move all terms containing z to the left, all other terms to the right

84z=1

z=1/84

z=1/84

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