40=2(2-2c)

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Solution for 40=2(2-2c) equation:



40=2(2-2c)
We move all terms to the left:
40-(2(2-2c))=0
We add all the numbers together, and all the variables
-(2(-2c+2))+40=0
We calculate terms in parentheses: -(2(-2c+2)), so:
2(-2c+2)
We multiply parentheses
-4c+4
Back to the equation:
-(-4c+4)
We get rid of parentheses
4c-4+40=0
We add all the numbers together, and all the variables
4c+36=0
We move all terms containing c to the left, all other terms to the right
4c=-36
c=-36/4
c=-9

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