40=2(4g-3)+14

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Solution for 40=2(4g-3)+14 equation: 



40=2(4g-3)+14

We move all terms to the left:

40-(2(4g-3)+14)=0



We calculate terms in parentheses: -(2(4g-3)+14), so:

2(4g-3)+14

We multiply parentheses

8g-6+14

We add all the numbers together, and all the variables

8g+8

Back to the equation:

-(8g+8)



We get rid of parentheses

-8g-8+40=0

We add all the numbers together, and all the variables

-8g+32=0

We move all terms containing g to the left, all other terms to the right

-8g=-32

g=-32/-8

g=+4

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