40=2(y-10)+3y

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Solution for 40=2(y-10)+3y equation: 



40=2(y-10)+3y

We move all terms to the left:

40-(2(y-10)+3y)=0



We calculate terms in parentheses: -(2(y-10)+3y), so:

2(y-10)+3y

We add all the numbers together, and all the variables

3y+2(y-10)

We multiply parentheses

3y+2y-20

We add all the numbers together, and all the variables

5y-20

Back to the equation:

-(5y-20)



We get rid of parentheses

-5y+20+40=0

We add all the numbers together, and all the variables

-5y+60=0

We move all terms containing y to the left, all other terms to the right

-5y=-60

y=-60/-5

y=+12

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