40=2x+(x/2)

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Solution for 40=2x+(x/2) equation: 



40=2x+(x/2)

We move all terms to the left:

40-(2x+(x/2))=0

We add all the numbers together, and all the variables

-(2x+(+x/2))+40=0

We multiply all the terms by the denominator


-(2x+(+x+40*2))=0



We calculate terms in parentheses: -(2x+(+x+40*2)), so:

2x+(+x+40*2)

We add all the numbers together, and all the variables

2x+(x+80)

We get rid of parentheses

2x+x+80

We add all the numbers together, and all the variables

3x+80

Back to the equation:

-(3x+80)



We get rid of parentheses

-3x-80=0

We move all terms containing x to the left, all other terms to the right

-3x=80

x=80/-3

x=-26+2/3

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