40=3(5-x)+8x

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Solution for 40=3(5-x)+8x equation: 



40=3(5-x)+8x

We move all terms to the left:

40-(3(5-x)+8x)=0

We add all the numbers together, and all the variables

-(3(-1x+5)+8x)+40=0



We calculate terms in parentheses: -(3(-1x+5)+8x), so:

3(-1x+5)+8x

We add all the numbers together, and all the variables

8x+3(-1x+5)

We multiply parentheses

8x-3x+15

We add all the numbers together, and all the variables

5x+15

Back to the equation:

-(5x+15)



We get rid of parentheses

-5x-15+40=0

We add all the numbers together, and all the variables

-5x+25=0

We move all terms containing x to the left, all other terms to the right

-5x=-25

x=-25/-5

x=+5

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