40=3c+8c+10

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Solution for 40=3c+8c+10 equation: 



40=3c+8c+10

We move all terms to the left:

40-(3c+8c+10)=0

We add all the numbers together, and all the variables

-(11c+10)+40=0

We get rid of parentheses

-11c-10+40=0

We add all the numbers together, and all the variables

-11c+30=0

We move all terms containing c to the left, all other terms to the right

-11c=-30

c=-30/-11

c=2+8/11

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