40=3x+6(3x-5)-14

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Solution for 40=3x+6(3x-5)-14 equation: 



40=3x+6(3x-5)-14

We move all terms to the left:

40-(3x+6(3x-5)-14)=0



We calculate terms in parentheses: -(3x+6(3x-5)-14), so:

3x+6(3x-5)-14

We multiply parentheses

3x+18x-30-14

We add all the numbers together, and all the variables

21x-44

Back to the equation:

-(21x-44)



We get rid of parentheses

-21x+44+40=0

We add all the numbers together, and all the variables

-21x+84=0

We move all terms containing x to the left, all other terms to the right

-21x=-84

x=-84/-21

x=+4

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