40=4(3c+1)

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Solution for 40=4(3c+1) equation: 



40=4(3c+1)

We move all terms to the left:

40-(4(3c+1))=0



We calculate terms in parentheses: -(4(3c+1)), so:

4(3c+1)

We multiply parentheses

12c+4

Back to the equation:

-(12c+4)



We get rid of parentheses

-12c-4+40=0

We add all the numbers together, and all the variables

-12c+36=0

We move all terms containing c to the left, all other terms to the right

-12c=-36

c=-36/-12

c=+3

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