40=4(x+1)-3(6x-4)

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Solution for 40=4(x+1)-3(6x-4) equation: 



40=4(x+1)-3(6x-4)

We move all terms to the left:

40-(4(x+1)-3(6x-4))=0



We calculate terms in parentheses: -(4(x+1)-3(6x-4)), so:

4(x+1)-3(6x-4)

We multiply parentheses

4x-18x+4+12

We add all the numbers together, and all the variables

-14x+16

Back to the equation:

-(-14x+16)



We get rid of parentheses

14x-16+40=0

We add all the numbers together, and all the variables

14x+24=0

We move all terms containing x to the left, all other terms to the right

14x=-24

x=-24/14

x=-1+5/7

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