40=4/5(m+7)

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Solution for 40=4/5(m+7) equation: 



40=4/5(m+7)

We move all terms to the left:

40-(4/5(m+7))=0



Domain of the equation: 5(m+7))!=0

m∈R



We multiply all the terms by the denominator


-(4+40*5(m+7))=0



We calculate terms in parentheses: -(4+40*5(m+7)), so:

4+40*5(m+7)

determiningTheFunctionDomain
40*5(m+7)+4

Wy multiply elements

200m(m+4

Back to the equation:

-(200m(m+4)





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

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We calculate terms in parentheses: -(200m(m+4), so:

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We calculate terms in parentheses: -(200m(m+4), so:

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We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

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200m(m+4





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200m(m+4





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200m(m+4





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200m(m+4





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200m(m+4





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200m(m+4





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200m(m+4





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We calculate terms in parentheses: -(200m(m+4), so:

200m(m+4





We calculate terms in parentheses: -(200m(m+4), so:

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We calcu

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