40=4f+12

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Solution for 40=4f+12 equation: 



40=4f+12

We move all terms to the left:

40-(4f+12)=0

We get rid of parentheses

-4f-12+40=0

We add all the numbers together, and all the variables

-4f+28=0

We move all terms containing f to the left, all other terms to the right

-4f=-28

f=-28/-4

f=+7

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