40=8(3x+2)-6(7+6x)

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Solution for 40=8(3x+2)-6(7+6x) equation:



40=8(3x+2)-6(7+6x)
We move all terms to the left:
40-(8(3x+2)-6(7+6x))=0
We add all the numbers together, and all the variables
-(8(3x+2)-6(6x+7))+40=0
We calculate terms in parentheses: -(8(3x+2)-6(6x+7)), so:
8(3x+2)-6(6x+7)
We multiply parentheses
24x-36x+16-42
We add all the numbers together, and all the variables
-12x-26
Back to the equation:
-(-12x-26)
We get rid of parentheses
12x+26+40=0
We add all the numbers together, and all the variables
12x+66=0
We move all terms containing x to the left, all other terms to the right
12x=-66
x=-66/12
x=-5+1/2

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