40=8(3x+2)-6(7+6x)

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Solution for 40=8(3x+2)-6(7+6x) equation: 



40=8(3x+2)-6(7+6x)

We move all terms to the left:

40-(8(3x+2)-6(7+6x))=0

We add all the numbers together, and all the variables

-(8(3x+2)-6(6x+7))+40=0



We calculate terms in parentheses: -(8(3x+2)-6(6x+7)), so:

8(3x+2)-6(6x+7)

We multiply parentheses

24x-36x+16-42

We add all the numbers together, and all the variables

-12x-26

Back to the equation:

-(-12x-26)



We get rid of parentheses

12x+26+40=0

We add all the numbers together, and all the variables

12x+66=0

We move all terms containing x to the left, all other terms to the right

12x=-66

x=-66/12

x=-5+1/2

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