40=80/x+x

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Solution for 40=80/x+x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

40 = x+80/x // - x+80/x

40-x-(80/x) = 0

40-x-80*x^-1 = 0

40*x^0-1*x^1-80*x^-1 = 0

(40*x^1-1*x^2-80*x^0)/(x^1) = 0 // * x^2

x^1*(40*x^1-1*x^2-80*x^0) = 0

x^1

40*x-x^2-80 = 0

40*x-x^2-80 = 0

DELTA = 40^2-(-80*(-1)*4)

DELTA = 1280

DELTA > 0

x = (1280^(1/2)-40)/(-1*2) or x = (-1280^(1/2)-40)/(-1*2)

x = (16*5^(1/2)-40)/(-2) or x = (-16*5^(1/2)-40)/(-2)

x in { (16*5^(1/2)-40)/(-2), (-16*5^(1/2)-40)/(-2)}

x in { (16*5^(1/2)-40)/(-2), (-16*5^(1/2)-40)/(-2) }

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