40=9(8-x)+13

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Solution for 40=9(8-x)+13 equation: 



40=9(8-x)+13

We move all terms to the left:

40-(9(8-x)+13)=0

We add all the numbers together, and all the variables

-(9(-1x+8)+13)+40=0



We calculate terms in parentheses: -(9(-1x+8)+13), so:

9(-1x+8)+13

We multiply parentheses

-9x+72+13

We add all the numbers together, and all the variables

-9x+85

Back to the equation:

-(-9x+85)



We get rid of parentheses

9x-85+40=0

We add all the numbers together, and all the variables

9x-45=0

We move all terms containing x to the left, all other terms to the right

9x=45

x=45/9

x=5

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