40=k+(k+3)+(k+2)+(k+7)

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Solution for 40=k+(k+3)+(k+2)+(k+7) equation: 



40=k+(k+3)+(k+2)+(k+7)

We move all terms to the left:

40-(k+(k+3)+(k+2)+(k+7))=0



We calculate terms in parentheses: -(k+(k+3)+(k+2)+(k+7)), so:

k+(k+3)+(k+2)+(k+7)

We get rid of parentheses

k+k+k+k+3+2+7

We add all the numbers together, and all the variables

4k+12

Back to the equation:

-(4k+12)



We get rid of parentheses

-4k-12+40=0

We add all the numbers together, and all the variables

-4k+28=0

We move all terms containing k to the left, all other terms to the right

-4k=-28

k=-28/-4

k=+7

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