40p2-90=0

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Solution for 40p2-90=0 equation:



40p^2-90=0
a = 40; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·40·(-90)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*40}=\frac{-120}{80} =-1+1/2 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*40}=\frac{120}{80} =1+1/2 $

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