40t2+80t+-60=0

Solution for 40t2+80t+-60=0 equation:

40t^2+80t+-60=0

We add all the numbers together, and all the variables

40t^2+80t=0

a = 40; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·40·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*40}=\frac{-160}{80}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*40}=\frac{0}{80}
=0
$