40x+(16x+(1/2x))=672

Solution for 40x+(16x+(1/2x))=672 equation:

40x+(16x+(1/2x))=672

We move all terms to the left:

40x+(16x+(1/2x))-(672)=0


Domain of the equation: 2x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

40x+(16x+(+1/2x))-672=0

We multiply all the terms by the denominator


40x*2x))+(16x+(-672*2x))+1=0

Wy multiply elements

80x^2-1344x=0

a = 80; b = -1344; c = 0;
Δ = b2-4ac
Δ = -13442-4·80·0
Δ = 1806336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1806336}=1344$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1344)-1344}{2*80}=\frac{0}{160}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1344)+1344}{2*80}=\frac{2688}{160}
=16+4/5
$