40x+(x-3)=468

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Solution for 40x+(x-3)=468 equation: 



40x+(x-3)=468

We move all terms to the left:

40x+(x-3)-(468)=0

We get rid of parentheses

40x+x-3-468=0

We add all the numbers together, and all the variables

41x-471=0

We move all terms containing x to the left, all other terms to the right

41x=471

x=471/41

x=11+20/41

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