40x+11=5(7x+3)+5x-4

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Solution for 40x+11=5(7x+3)+5x-4 equation: 



40x+11=5(7x+3)+5x-4

We move all terms to the left:

40x+11-(5(7x+3)+5x-4)=0



We calculate terms in parentheses: -(5(7x+3)+5x-4), so:

5(7x+3)+5x-4

We add all the numbers together, and all the variables

5x+5(7x+3)-4

We multiply parentheses

5x+35x+15-4

We add all the numbers together, and all the variables

40x+11

Back to the equation:

-(40x+11)



We get rid of parentheses

40x-40x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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