40x+16x+((1/2)x))=672

Solution for 40x+16x+((1/2)x))=672 equation:

40x+16x+((1/2)x))=672

We move all terms to the left:

40x+16x+((1/2)x))-(672)=0


Domain of the equation: 2)x))-672!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

40x+16x+((+1/2)x))-672=0

We add all the numbers together, and all the variables

56x+((+1/2)x))-672=0

We multiply all the terms by the denominator


56x*2)x))-672+((+1=0

Wy multiply elements

112x^2=0

a = 112; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·112·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{224}=0$