40x-(2+12x)=8(14x-3)

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Solution for 40x-(2+12x)=8(14x-3) equation: 



40x-(2+12x)=8(14x-3)

We move all terms to the left:

40x-(2+12x)-(8(14x-3))=0

We add all the numbers together, and all the variables

40x-(12x+2)-(8(14x-3))=0

We get rid of parentheses

40x-12x-(8(14x-3))-2=0



We calculate terms in parentheses: -(8(14x-3)), so:

8(14x-3)

We multiply parentheses

112x-24

Back to the equation:

-(112x-24)



We add all the numbers together, and all the variables

28x-(112x-24)-2=0

We get rid of parentheses

28x-112x+24-2=0

We add all the numbers together, and all the variables

-84x+22=0

We move all terms containing x to the left, all other terms to the right

-84x=-22

x=-22/-84

x=11/42

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