40x-18+3x=32(5+x)

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Solution for 40x-18+3x=32(5+x) equation: 



40x-18+3x=32(5+x)

We move all terms to the left:

40x-18+3x-(32(5+x))=0

We add all the numbers together, and all the variables

40x+3x-(32(x+5))-18=0

We add all the numbers together, and all the variables

43x-(32(x+5))-18=0



We calculate terms in parentheses: -(32(x+5)), so:

32(x+5)

We multiply parentheses

32x+160

Back to the equation:

-(32x+160)



We get rid of parentheses

43x-32x-160-18=0

We add all the numbers together, and all the variables

11x-178=0

We move all terms containing x to the left, all other terms to the right

11x=178

x=178/11

x=16+2/11

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