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40x^2+52x+12=0
a = 40; b = 52; c = +12;
Δ = b2-4ac
Δ = 522-4·40·12
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-28}{2*40}=\frac{-80}{80} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+28}{2*40}=\frac{-24}{80} =-3/10 $
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