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40x^2-30x=135
We move all terms to the left:
40x^2-30x-(135)=0
a = 40; b = -30; c = -135;
Δ = b2-4ac
Δ = -302-4·40·(-135)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-150}{2*40}=\frac{-120}{80} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+150}{2*40}=\frac{180}{80} =2+1/4 $
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