40y-10+1y=10y+4y-1-63

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Solution for 40y-10+1y=10y+4y-1-63 equation: 



40y-10+1y=10y+4y-1-63

We move all terms to the left:

40y-10+1y-(10y+4y-1-63)=0

We add all the numbers together, and all the variables

40y+1y-(14y-64)-10=0

We add all the numbers together, and all the variables

41y-(14y-64)-10=0

We get rid of parentheses

41y-14y+64-10=0

We add all the numbers together, and all the variables

27y+54=0

We move all terms containing y to the left, all other terms to the right

27y=-54

y=-54/27

y=-2

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