40y-10=12(y+3)

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Solution for 40y-10=12(y+3) equation:


Simplifying
40y + -10 = 12(y + 3)

Reorder the terms:
-10 + 40y = 12(y + 3)

Reorder the terms:
-10 + 40y = 12(3 + y)
-10 + 40y = (3 * 12 + y * 12)
-10 + 40y = (36 + 12y)

Solving
-10 + 40y = 36 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
-10 + 40y + -12y = 36 + 12y + -12y

Combine like terms: 40y + -12y = 28y
-10 + 28y = 36 + 12y + -12y

Combine like terms: 12y + -12y = 0
-10 + 28y = 36 + 0
-10 + 28y = 36

Add '10' to each side of the equation.
-10 + 10 + 28y = 36 + 10

Combine like terms: -10 + 10 = 0
0 + 28y = 36 + 10
28y = 36 + 10

Combine like terms: 36 + 10 = 46
28y = 46

Divide each side by '28'.
y = 1.642857143

Simplifying
y = 1.642857143

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