40y-5=5(8y-1)

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Solution for 40y-5=5(8y-1) equation: 



40y-5=5(8y-1)

We move all terms to the left:

40y-5-(5(8y-1))=0



We calculate terms in parentheses: -(5(8y-1)), so:

5(8y-1)

We multiply parentheses

40y-5

Back to the equation:

-(40y-5)



We get rid of parentheses

40y-40y+5-5=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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